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Dr. Dread · Posted: Thu Feb 07, 2002 11:42 am Post subject: @HEX() function

I use the @HEX() function to format some values. My problem is that if the resulting hex number has one or more leading zeros, @HEX() will remove them automatically (i.e. 01234 will be 1234).

Normally that would not be an issue, but in this case I really to keep leading zeros. Anyone has an idea how to do this?

Thanks.

Dr. Dread

Mac · Posted: Thu Feb 07, 2002 7:46 pm Post subject:

How about a loop to check for leading zeroes before
the @hex() function, save them, and append the
@hex() result to the zeroes?

Something like this maybe:
__________________________________________________________________________________________________________________________

Dr. Dread · Posted: Fri Feb 08, 2002 7:42 am Post subject:

Hi again, Mac!

Thanks for the suggestion. But I don't think that it will work because input values do not necessarily have any leading 0's - they appear in hex output, or rather they don't because the @hex() function removes them.

Let me give you an example:

Tommy · Posted: Fri Feb 08, 2002 12:29 pm Post subject:

The following may be what you want:

Dr. Dread · Posted: Fri Feb 08, 2002 1:52 pm Post subject:

I had tried that one (defining length of @hex() output) already. It works fine, but only when working with fixed-length values. Problem is that my input (and therefore output) has varying length.

But hey, it gives me an idea now. There just might be a way for me to determine the expected length of each @hex() output - if that's possible I can follow your suggestion..

%i = 121843147
%%length = "expected length"
%o = @hex(%I,%%length)

I will try to rewrite my routines and see if this puppy will run! Thanks

Dread Cool